
FR=Iα⇒I=αFR=210×0.2=1 kg−m2
JEE Main 2025 — Physics Mechanics

A wheel of radius 0.2 m rotates freely about its center when a string that is wrapped over its rim is pulled by force of 10 N as shown in figure. The established torque produces an angular acceleration of 2 rad/s2. Moment of inertia of the wheel is _____ kgm2.
(Acceleration due to gravity =10 m/s2)
Held on 2 Apr 2025 · Verified 6 Jul 2026.
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