
d=23a Angular momentum of one mass about point O $\begin{aligned}
L & =m v d \
& =m v_0 \cdot \frac{a}{2 \sqrt{3}}
\end{aligned}NetangularmomentumaboutpointO\begin{aligned}
L_{\text {net }} & =32 \
& =\frac{\sqrt{3} m v_0 a}{2}
\end{aligned}$
JEE Main 2025 — Physics Mechanics

Three equal masses m are kept at vertices (A, B, C) of an equilateral triangle of side a in free space. At t=0, they are given an initial velocity VA=V0AC,VB=V0BA and VC=V0CB. Here, AC,CB and BA are unit vectors along the edges of the triangle. If the three masses interact gravitationally, then the magnitude of the net angular momentum of the system at the point of collision is :
Held on 29 Jan 2025 · Verified 6 Jul 2026.
3amV0
23 a mV0
23 a mV0
21 a mV0
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