ω=π3×2π=6rad/sR=Lsinθ 
and T=Mg2+ω4R2 Also, Tsinθ=Mω2⋅Lsinθ $\begin{aligned}
& \Rightarrow \quad T=M(36) \mathrm{L} \
& \Rightarrow \quad T=36 \mathrm{ML}
\end{aligned}$

A string of length L is fixed at one end and carries a mass of M at the other end. The mass makes (π3) rotations per second about the vertical axis passing through end of the string as shown. The tension in the string is …… ML.
Held on 24 Jan 2025 · Verified 6 Jul 2026.
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