
$\begin{aligned}
& \mathrm{H}=\frac{\left(\frac{\mathrm{v}_0}{\sqrt{2}}\right)^2}{2 \mathrm{g}}=\frac{\mathrm{v}_0^2}{4 \mathrm{g}} \
& \mathrm{L}=\mathrm{mvh} \
& \mathrm{L}=\mathrm{m} \frac{\mathrm{v}_0}{\sqrt{2}} \frac{\mathrm{v}_0^2}{4 \mathrm{~g}}
\end{aligned}$