
Since least count of the instrument can be calculated as $\begin{aligned}
& \text { Least count }=\frac{\text { pitch length }}{\text { No. of division on circular scale }} \
& =\frac{0.75}{15}=0.05 \mathrm{mm} .
\end{aligned}Hereweareprovided\mathrm{L}=5 \mathrm{mm} & \mathrm{W}=2.5 \mathrm{mm}\mathrm{L}=5 \mathrm{mm} & \mathrm{W}=2.5 \mathrm{mm}\becauseWeknowthat\mathrm{A}=\mathrm{L} . \mathrm{W}Forcalculatingfractionalerror,wecanwrite\frac{\mathrm{dA}}{\mathrm{A}}=\frac{\mathrm{dL}}{\mathrm{L}}+\frac{\mathrm{dW}}{\mathrm{W}}Here\mathrm{dL}=\mathrm{dW}=0.05 \mathrm{mm}\begin{aligned}
& \frac{\mathrm{dA}}{\mathrm{A}}=\frac{0.05}{5}+\frac{0.05}{2.5} \
& \Rightarrow \frac{\mathrm{dA}}{\mathrm{~A}}=\frac{1}{100}+\frac{2}{100}=\frac{3}{100}
\end{aligned}So,x=3$