ℓ=2 m;Y=2×1011 m2 Nμ=−(ℓΔℓ)(rΔr)⇒ℓΔℓ=μ1×(rΔr)=0.21×(10−3)
⇒ℓΔℓ=5×10−3u=21yεℓ2=21×2×1011×[5×10−3]2=25
A steel wire of length 2 m and Young's modulus 2.0×1011Nm−2 is stretched by a force. If Poisson ratio and transverse strain for the wire are 0.2 and 10−3 respectively, then the elastic potential energy density of the wire is _______ ×105 (in SI units)
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