When sphere is of radius R, its mass is M, when radius is reduced to 2R, mass will reduced to 8M Now by conservation of angular momentum
$\begin{aligned}
& \left(\tau_{e x t}=0\right) \
& L_1=L_2 \
& I_1 \omega_1=I_2 \omega_2 \
& \left(\frac{2}{5} M R^2\right) \omega_1=\left(\frac{2}{5}\left(\frac{\mathrm{M}}{8}\right)\left(\frac{\mathrm{R}}{2}\right)^2\right) \omega_2
\end{aligned}$
ω2=32ω1 value of x is 32
Answer is 32