KE=21mv2=21 mrGMe=2rGMem=2(RE+h)GMem=2(6.4×106+2.7×105)6.67×10−11×6×1024×6.4×106=3×1010 J
A satellite of mass 1000 kg is launched to revolve around the earth in an orbit at a height of 270 km from the earth's surface. Kinetic energy of the satellite in this orbit is ______ ×1010 J.
(Mass of earth =6×1024 kg, Radius of earth = 6.4×106 m, Gravitational constant =
6.67×10−11Nm2 kg−2)
Held on 2 Apr 2025 · Verified 6 Jul 2026.
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