Given, Initial pressure of liquid (Pi)=1 atm
Final pressure of liquid (Pf)=5 atm
Change in pressure (dP)=Pf−Pi=4 atm
=4×105 Pa
Change in volume (dV)=−0.8 cm3
Bulk modulus (B)=2×109 Pa
Now, B=(dV/V)−dP⇒V=−B(dPdV)
$\begin{aligned}
\Rightarrow & V=-2 \times 10^9 \times \frac{\left(-0.8 \times 10^{-6}\right)}{4 \times 10^5} \
& =4 \times 10^{-3} \mathrm{~m}^3=4 \text { litre }
\end{aligned}$