Range =3Hmax gu2sin2θ=2 g3u2sin2θ
2sinθcosθ=23sin2θ
tanθ=34⇒θ=53∘
R=gu2(2×53×54)⇒25 g24u2
A particle is projected with velocity u so that its horizontal range is three times the maximum height attained by it. The horizontal range of the projectile is given as 25gnu2, where value of n is : (Given ' g ' is the acceleration due to gravity).
Held on 3 Apr 2025 · Verified 6 Jul 2026.
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