
u=360×185=100 m/sx=u×t=2×103 mt=g2H⇒H=2t2 gH=2400×10H=2000 mD=x2+H2D=22 km
A helicopter flying horizontally with a speed of 360 km/h at an altitude of 2 km , drops an object at an instant. The object hits the ground at a point O , 20 s after it is dropped. Displacement of ' O ' from the position of helicopter where the object was released is :
(use acceleration due to gravity g=10 m/s2 and neglect air resistance)
Held on 7 Apr 2025 · Verified 6 Jul 2026.
25 km
4 km
7.2 km
22 km
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