
Torque about bottom point
$\begin{aligned}
& \mathrm{F} \times 2 \mathrm{r}=\mathrm{I} \alpha \
& 49 \times 2 \mathrm{r}=\frac{7}{5} \mathrm{mr}^2 \alpha \
& 14=4 \mathrm{r} \alpha
\end{aligned}$
As sphere rolls without slipping
$\begin{aligned}
& \mathrm{a}=\mathrm{r} \alpha \
& \mathrm{a}=\frac{14}{4}=\frac{7}{2}=3.5 \mathrm{~m} / \mathrm{s}^2
\end{aligned}$
