F=α+βx2 Work done ∫dw=∫F⋅dx $\begin{aligned}
& \Rightarrow \quad \Delta W=\int F \cdot d x=\int\left(\alpha+\beta x^2\right) d x \
& \Rightarrow \quad \Delta W=\left|\alpha x+\frac{\beta x^3}{3}\right|_0^1=\alpha+\frac{\beta}{3}=5
\end{aligned}Given\alpha=1So,\frac{\beta}{3}=4\Rightarrow \beta=12 \mathrm{~N} / \mathrm{m}^2$