
Block travels with uniform velocity
So a=0⇒ Fcos45∘= friction
$\begin{aligned}
& \frac{\mathrm{F}}{\sqrt{2}}=\mu\left[\mathrm{mg}-\frac{\mathrm{F}}{\sqrt{2}}\right] \
& \frac{\mathrm{F}}{\sqrt{2}}=0.25\left[25 \times 9.8-\frac{\mathrm{F}}{\sqrt{2}}\right] \
& \Rightarrow \quad 1.25 \frac{\mathrm{F}}{\sqrt{2}}=61.25 \
& \mathrm{F}=\frac{61.25 \times \sqrt{2}}{1.25}=49 \sqrt{2} \
& \mathrm{W}_{\mathrm{ext}}=\mathrm{FS} \cos 45^{\circ} \
&=49 \sqrt{2} \times 5 \times \frac{1}{\sqrt{2}}=245 \mathrm{J}
\end{aligned}$