
$\begin{aligned}
& F-m g=m a \
& F=m a+m g \
& F-(m-x) g=(m-x) 3 a
\end{aligned}PutF\begin{aligned}
& \mathrm{Ma}+\mathrm{mg}-\mathrm{mg}+\mathrm{xg}=3 \mathrm{ma}-3 \mathrm{xa} \
& \mathrm{x}=\frac{2 \mathrm{ma}}{\mathrm{~g}+3 \mathrm{a}}
\end{aligned}$