Volume of cube inside water $\begin{aligned}
& =\left(\frac{\text { Denslty of cube }}{\text { Denslty of water }}\right) \times \text { Volume of cube } \
& =\frac{\text { Mass of cube }}{\text { Denslty of water }} \
& =\frac{400 \mathrm{gm}}{1 \mathrm{gm} / \mathrm{cm}^3} \
& =400 \mathrm{cm}^3
\end{aligned}Volumeofcubeoutsidewater\begin{aligned}
& =\text { Volume of cube }- \text { Volume of cube inside water } \
& =1000 \mathrm{cm}^3-400 \mathrm{cm}^3 \
& =600 \mathrm{cm}^3
\end{aligned}$
A 400 g solid cube having an edge of length 10 cm floats in water. How much volume of the cube is outside the water ? (Given : density of water =1000…
JEE Main 2025 — Physics Mechanics
A 400 g solid cube having an edge of length 10 cm floats in water. How much volume of the cube is outside the water ? (Given : density of water =1000 kg m−3 )
Held on 28 Jan 2025 · Verified 6 Jul 2026.
Options
- A
1400 cm3
- B
600 cm3
- C
4000 cm3
- D
400 cm3
Did you get this right?
Sign in to track your attempts and accuracy.
Your note
Sign in to keep a private note on this question. Nothing you write is ever public.
JEE Main Mechanics in other years
More JEE Main Mechanics questions
If $\epsilon, E$ and $t$ represent the free space permittivity, electric field and time respectively, then the unit of $\frac{\epsilon E}{t}$ will be :
When a part of a straight capillary tube is placed vertically in a liquid, the liquid raises upto certain height $h$. If the inner radius of the capillary tube, density of the liquid and surface tension of the liquid decrease by $1 \%$ each, then the height of the liquid in the tube will change by $\%$.
The velocity of a particle is given as $\vec{v} = -x\hat{i} + 2y\hat{j} - z\hat{k}$ m/s. The magnitude of acceleration at point $(1, 2, 4)$ is _______ m/s$^2$.
Suppose there is a uniform circular disc of mass $M \mathrm{~kg}$ and radius $r \mathrm{~m}$ shown in figure. The shaded regions are cut out from the disc. The moment of inertia of the remainder about the axis $A$ of the disc is given by $\frac{x}{256} M r^{2}$. The value of $x$ is $\_\_\_\_$. 
A soap bubble of surface tension $0.04 \mathrm{~N} / \mathrm{m}$ is blown to a diameter of 7 cm. If $(15000-x) \mu \mathrm{J}$ of work is done in blowing it further to make its diameter 14 cm, then the value of $x$ is $\_\_\_\_$. ($\pi=22 / 7$)
Other Physics topics for JEE Main
Keep practicing Mechanics
Work through every JEE Main Mechanics PYQ, year by year.