MSR=1 mm,CSR=42, pitch =1 mmLC= No. of CSD pitch =(1001)=0.01 mm Diameter =MSR+LC×CSD Diameter =1+(0.01)×42 mm Diameter =1.42 mm=50x∴x=71
While measuring diameter of wire using screw gauge the following readings were noted. Main scale reading is 1 ~mm and circular scale reading is equal…
JEE Main 2024 — Physics Mechanics
While measuring diameter of wire using screw gauge the following readings were noted. Main scale reading is 1 mm and circular scale reading is equal to 42 divisions. Pitch of screw gauge is 1 mm and it has 100 divisions on circular scale. The diameter of the wire is 50x mm. The value of x is :
Held on 6 Apr 2024 · Verified 6 Jul 2026.
Options
- A
21
- B
142
- C
71
- D
42
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