Kinetic energy (K)=2mP2 ⇒P=2mK
If Kf=36Ki So, Pf=6Pi $\begin{aligned}
% \text { increase in momentum } & =\frac{\mathrm{P}{\mathrm{f}}-\mathrm{P}{\mathrm{i}}}{\mathrm{P}{\mathrm{i}}} \times 100 % \
& =\frac{6 \mathrm{P}{\mathrm{i}}-\mathrm{P}{\mathrm{i}}}{\mathrm{P}{\mathrm{i}}} \times 100 % \
& =500 %
\end{aligned}$