Applying conservation of angular momentum, we get
I1ω1+I2ω2=(I1+I2)ω0⇒4×10+2×4=(4+2)ω0⇒ω0=8rads−1
Now, initial rotational kinetic energy is E1=21I1ω12+21I2ω22=216J
and final rotational kinetic energy is
E2=21(I1+I2)ω02=192J
Required, energy loss ΔE=E1−E2=24J