Taking g=9.8 m/s2 
294−N=30×0.1 N=291
JEE Main 2024 — Physics Mechanics
A wooden block of mass 5 kg rests on a soft horizontal floor. When an iron cylinder of mass 25 kg is placed on the top of the block, the floor yields and the block and the cylinder together go down with an acceleration of 0.1 ms−2. The action force of the system on the floor is equal to:
Held on 5 Apr 2024 · Verified 6 Jul 2026.
196 N
291 N
294 N
297 N
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If $\epsilon, E$ and $t$ represent the free space permittivity, electric field and time respectively, then the unit of $\frac{\epsilon E}{t}$ will be :
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