Ignoring buoyancy force, we can write terminal velocity as
mg=6πηrv
⇒v∝r1 (as mass is constant)
Now, v′v=rr′
Asr′=2r
So v′=2v
JEE Main 2024 — Physics Mechanics
A small spherical ball of radius r, falling through a viscous medium of negligible density has terminal velocity v. Another ball of the same mass but of radius 2r, falling through the same viscous medium will have terminal velocity:
Held on 31 Jan 2024 · Verified 6 Jul 2026.
2v
4v
4v
2v
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