Linear momentum will be conserved, therefore
mu=(M+m)V
⇒10−2×2×102≅1×V
⇒V≅2ms−1
Again from energy conservation, we get height achieved, h=2gV2=0.2m.
A simple pendulum of length 1m has a wooden bob of mass 1kg. It is struck by a bullet of mass 10−2kg moving with a speed of 2×102ms−1. The bullet gets embedded into the bob. The height to which the bob rises before swinging back is. (use g=10ms−2)
Held on 1 Feb 2024 · Verified 6 Jul 2026.
0.30m
0.20m
0.35m
0.40m
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