Given, ux=5ms−1,ax=3ms−2,x=84m
The formula to calculate the velocity of the particle along x-axis is given by
vx2=ux2+2ax...(1)
From equation (1), it follows that
vx2=25+2(3)(84)⇒vx=23ms−1
Also, the velocity of the particle along x-axis can be written as
vx=ux+axt...(2)
From equation (2), it follows that
t==323−56s
Similarly, for the y− component of the velocity, it follows that
vy===0+ayt0+2×(6)12ms−1
Hence, the magnitude of the velocity is given by
v2=vx2+vy2=232+122=673v=673ms−1
Therefore, α=673.