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A particle moves in x-y plane under the influence of a force F such that its linear momentum is overrightarrow ( t)= i cos ( kt)- j sin ( kt). If k…

JEE Main 2024 — Physics Mechanics

2024mcqmedium

A particle moves in x−yx-yx−y plane under the influence of a force F⃗\vec{F}F such that its linear momentum is p→(t)=i^cos⁡(kt)−j^sin⁡(kt)\overrightarrow{\mathrm{p}}(\mathrm{t})=\hat{i} \cos (\mathrm{kt})-\hat{j} \sin (\mathrm{kt})p​(t)=i^cos(kt)−j^​sin(kt). If k\mathrm{k}k is constant, the angle between F→\overrightarrow{\mathrm{F}}F and p→\overrightarrow{\mathrm{p}}p​ will be :

Official previous-year question

Held on 5 Apr 2024 · Verified 6 Jul 2026.

Options

  1. A

    π4\frac{\pi}{4}4π​

  2. B

    π6\frac{\pi}{6}6π​

  3. C

    π2\frac{\pi}{2}2π​

  4. D

    π3\frac{\pi}{3}3π​

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