A cylinder is rolling down on an inclined plane of inclination 60°. Its acceleration during rolling down will be x √3ms^-2, where x= (use g=10ms^-2).
JEE Main 2024 — Physics Mechanics
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A cylinder is rolling down on an inclined plane of inclination 60∘. Its acceleration during rolling down will be 3xms−2, where x= _______(use g=10ms−2).
Official previous-year question
Held on 29 Jan 2024 · Verified 6 Jul 2026.
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Solution
For rolling motion, the acceleration of the cylinder along the inclined plane can be expressed as
a=1+MR2Icmgsinθ...(1)
The moment of inertia of the cylinder can be written as
Icm=21MR2...(2)
From equations (1) and (2), it follows that
a===1+21gsinθ32×10×23310ms−2
Therefore, x=10.
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