
For rolling motion, the acceleration of the cylinder along the inclined plane can be expressed as
a=1+MR2Icmgsinθ...(1)
The moment of inertia of the cylinder can be written as
Icm=21MR2...(2)
From equations (1) and (2), it follows that
a===1+21gsinθ32×10×23310ms−2
Therefore, x=10.