v1= volume immersed in water. v2= volume immersed in oil. v1ρwg+v2ρog=(v1+v2)ρcgv1+ρwv2ρo=(v1+v2)ρwρc=v1+0.8v2=0.9v1+0.9v2=0.1v1=0.1v2v1:v2=1:1
A cube of ice floats partly in water and partly in kerosene oil. The ratio of volume of ice immersed in water to that in kerosene oil (specific…
JEE Main 2024 — Physics Mechanics
A cube of ice floats partly in water and partly in kerosene oil. The ratio of volume of ice immersed in water to that in kerosene oil (specific gravity of Kerosene oil =0.8, specific gravity of ice =0.9) 
Held on 8 Apr 2024 · Verified 6 Jul 2026.
Options
- A
1:1
- B
5:4
- C
8:9
- D
9:10
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