Ki Kf% loss =21 m(100)2=21 m(40)2=Ki∣Kf−Ki∣×100=21 m(100)221 m(40)2−21 m(100)2×100=100∣1600−100×100∣=84%
A bullet of mass 50 ~g is fired with a speed 100 ~m / s on a plywood and emerges with 40 ~m / s. The percentage loss of kinetic energy is :
JEE Main 2024 — Physics Mechanics
A bullet of mass 50 g is fired with a speed 100 m/s on a plywood and emerges with 40 m/s. The percentage loss of kinetic energy is :
Held on 6 Apr 2024 · Verified 6 Jul 2026.
Options
- A
84%
- B
16%
- C
32%
- D
44%
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