
100=vg2H;x=2vg2(4H)=vg2H⇒x=100
JEE Main 2024 — Physics Mechanics
A body of mass M thrown horizontally with velocity v from the top of the tower of height H touches the ground at a distance of 100 m from the foot of the tower. A body of mass 2M thrown at a velocity 2v from the top of the tower of height 4H will touch the ground at a distance of _____m.
Held on 8 Apr 2024 · Verified 6 Jul 2026.
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