Net force F=F1+F2=8i^+4j^+4k^
Therefore, required acceleration a=mF=2i^+j^+k^
JEE Main 2024 — Physics Mechanics
A body of mass 4kg experiences two forces F1=5i^+8j^+7k^ and F2=3i^−4j^−3k.^ The acceleration acting on the body is:
Held on 1 Feb 2024 · Verified 6 Jul 2026.
−2i^−j^−k^
4i^+2j^+2k^
2i^+j^+k^
2i^+3j^+3k^
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