It is given that A=2i^+3j^+2k^.
By the given condition,
B−(2i^+3j^+2k^)=2j^
⇒B=2i^+5j^+2k^
The magnitude is given by the formula,∣B∣=B2x+B2y+B2z
⇒∣B∣=4+25+4=33
When vector A=2 i+3 j+2 k is subtracted from vector B, it gives a vector equal to 2 j. Then the magnitude of vector B will be:
JEE Main 2023 — Physics Mechanics
When vector A=2i^+3j^+2k^ is subtracted from vector B, it gives a vector equal to 2j^. Then the magnitude of vector B will be:
Held on 11 Apr 2023 · Verified 1 Jul 2026.
Options
- A
5
- B
3
- C
6
- D
33
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