A meter bridge consists of a wire of length 1m and of uniform cross-sectional area stretched taut and clamped between two thick metallic strips bent at right angles with two gaps across which resistors are to be connected. It works on the principle of the Wheatstone bridge. Therefore, we can write
10R1+R2=4060⇒R1+R2=15Ω
Then for the second case, we can write
(R1+R2)×3R1R2=6040⇒R1R2=30Ω2