The force acting on steel wire F is (2+1.14)g=3.14g
From the relation of Young's modulus, it can be written
AF=Y(LΔL)
⇒ΔL=(AYFL)=π×(0.2)2×2×1011×10−43.14×g×1.6
⇒ΔL=2×10−5
⇒ΔL=20×10−6m
Two wires each of radius 0.2cm and negligible mass, one made of steel and the other made of brass are loaded as shown in the figure. The elongation of the steel wire is ______10–6m. [Young's modulus for steel =2×1011Nm–2 and g=10ms–2]

Held on 10 Apr 2023 · Verified 6 Jul 2026.
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