For a parallel combination the equivalent resistance is
R1=R11+R21...(i)
A general expression for error can be written as x±Δx
Differentiating equation (i)
R2dR=R12dR1+R22dR2...(ii)
The equivalent resistance with {R}_{1}=10\Omega &{R}_{2}=15\Omega is
R1=101+151
⇒R=25150=6Ω
Substituting the above value in equation (ii)
dR=36(1000.5+15×150.5)=0.26
⇒R=6±0.26
Hence, the percentage error is
RdR×100=60.26×100=4.33