Two identical particles each of mass m go round a circle of radius a under the action of their mutual gravitational attraction. The angular speed of…
JEE Main 2023 — Physics Mechanics
2023mcqmedium
Two identical particles each of mass m go round a circle of radius a under the action of their mutual gravitational attraction. The angular speed of each particle will be :
Official previous-year question
Held on 15 Apr 2023 · Verified 6 Jul 2026.
Options
A
a3Gm
B
8a3Gm
C
4a3Gm
D
2a3Gm
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Solution
The gravitational force (FG) between the particles is given by
FG==(2a)2Gm24a2Gm2...(1)
The centripetal force (FC) of each particle can be written as
FC=mω2a...(2)
Under balanced condition, equate equation (1) and equation (2) and simplify to obtain the angular speed of each particle.
mω2a=⇒⇒4a2Gm2ω2=4a3Gmω=4a3Gm
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