When the force F1 is removed, the particle starts accelerating because of the resultant force between F2 and F3.
The resultant force can be calculated as follows:
F==F22+F3210N
Hence, the acceleration of the particle is given by
a==5kg10N2ms–2
Three forces F_1=10N,F_2=8N,F_3=6N are acting on a particle of mass 5 kg. The forces F_2 and F_3 are applied perpendicularly so that particle remains…
JEE Main 2023 — Physics Mechanics
Three forces F1=10N,F2=8N,F3=6N are acting on a particle of mass 5kg. The forces F2 and F3 are applied perpendicularly so that particle remains at rest. If the force F1 is removed, then the acceleration of the particle is
Held on 12 Apr 2023 · Verified 1 Jul 2026.
Options
- A
7ms–2
- B
0.5ms–2
- C
4.8ms–2
- D
2ms–2
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