The pressure inside the bubble is given by
ΔP=P−P0=ρgh+r2T
The data given is
r=10−3mT=0.075Nm−1ρ=1000kgm−3h=10cm
Therefore, the pressure in the bubble is
ΔP=(1000×10×10×10−2)+10−32×0.075=1000+150=1150Pa
JEE Main 2023 — Physics Mechanics
There is an air bubble of radius 1.0mm in a liquid of surface tension 0.075Nm–1 and density 1000kgm–3 at a depth of 10cm below the free surface. The amount by which the pressure inside the bubble is greater than the atmospheric pressure is _______ Pa(g=10ms−2).
Held on 15 Apr 2023 · Verified 6 Jul 2026.
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