
At maximum height, only horizontal velocity of the particle remains. Let the angle of project be θ. The horizontal velocity of the particle will remain same, therefore
ucosθ=23u⇒θ=30∘
Now, time of flight of projectile is
T=g2usinθ=gu
The initial speed of a projectile fired from ground is u. At the highest point during its motion, the speed of projectile is 23u. The time of flight of the projectile is:
Held on 31 Jan 2023 · Verified 6 Jul 2026.
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