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The equation of a circle is given by x^2+y^2=a^2, where a is the radius. If the equation is modified to change the origin other than (0,0), then find…

JEE Main 2023 — Physics Mechanics

2023mcqmedium

The equation of a circle is given by x2+y2=a2{x}^{2}+{y}^{2}={a}^{2}x2+y2=a2, where aaa is the radius. If the equation is modified to change the origin other than (0,0)(0,0)(0,0), then find out the correct dimensions of AAA and BBB in a new equation :

(x−At)2+(y−tB)2=a2{(x-At)}^{2}+{(y-\frac{t}{B})}^{2}={a}^{2}(x−At)2+(y−Bt​)2=a2

The dimensions of ttt is given as [T−1][{T}^{-1}][T−1]

Official previous-year question

Held on 29 Jan 2023 · Verified 6 Jul 2026.

Options

  1. A

    A=[L–1T],B=[LT–1]A=[{L}^{–1}T],B=[{\mathrm{LT}}^{–1}]A=[L–1T],B=[LT–1]

  2. B

    A=[LT],B=[L–1T–1]A=[\mathrm{LT}],B=[{L}^{–1}T{}^{–1}]A=[LT],B=[L–1T–1]

  3. C

    A=[L–1T–1],B=[LT–1]A=[{L}^{–1}T{}^{–1}],B=[{\mathrm{LT}}^{–1}]A=[L–1T–1],B=[LT–1]

  4. D

    A=[L–1T–1],B=[LT]A=[{L}^{–1}{T}^{–1}],B=[\mathrm{LT}]A=[L–1T–1],B=[LT]

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