The least count is LC=0.1mm
Zero error (ZE)=6×LC=6×0.1mm=0.6mm
The total reading is TR=MSR+(VSR×LC)−ZE⇒TR=32mm+(0.1×4)mm−0.6mm⇒TR=31.8mm=3.18cm
JEE Main 2023 — Physics Mechanics
In an experiment with vernier callipers of least count 0.1mm, when two jaws are joined together the zero of vernier scale lies right to the zero of the main scale and 6th division of vernier scale coincides with the main scale division. While measuring the diameter of a spherical bob, the zero of vernier scale lies in between 3.2cm and 3.3cm marks and 4th division of vernier scale coincides with the main scale division. The diameter of bob is measured as
Held on 10 Apr 2023 · Verified 6 Jul 2026.
3.22cm
3.18cm
3.26cm
3.25cm
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