Given:
50VSD=49MSD⇒1VSD=5049MSD
So least count will be
=1MSD−1VSD=201cm−5049⋅201cm
=501×201cm=0.01mm
As we know, μ=h′h=5.005.25
Applying log on both sides, we get
lnμ=lnh–lnh’
Differentiating both sides, we get
μdμ=hdh−h′dh′
For calculation, all errors will be added, therefore
dμ=[5.250.01+5.000.01]μ
=1041×10−3
Hence, x=41