Case 1: No shunt is added
The initial balancing length l of the bridge is,
32=100−ll
⇒200−2l=3l⇒l=40cm
Case 2: When shunt is added
The new balancing length is, l1=22.5+40=62.5cm
So, 37.562.5=(3+X3X)2
⇒X=2.
JEE Main 2023 — Physics Mechanics
In a metre bridge experiment the balance point is obtained if the gaps are closed by 2Ω and 3Ω. A shunt of XΩ is added to 3Ω resistor to shift the balancing point by 22.5cm. The value of X is ______.
Held on 29 Jan 2023 · Verified 6 Jul 2026.
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