From Kepler's law of periods, we know that
T2∝R3⇒(T2T1)2=(R2R1)3
⇒(2.831)2=(R21.5×106)3
⇒R2=[(2.83)2×(1.5×106)3]31
=831×1.5×106=3×106km
If the distance of the earth from Sun is 1.5×106km, then the distance of an imaginary planet from Sun, if its period of revolution is 2.83 years is:
Held on 24 Jan 2023 · Verified 6 Jul 2026.
6×107km
6×106km
3×106km
3×107km
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