
It is given that
A1=10cm2;A2=5cm2
ΔP=3Nm−2
By continuity equation,
A1v1=A2v2⇒v1=A1A2v2...(i)
By Bernoulli's equation,
21ρv22−21ρv12=ΔP...(ii)
Using equation (i) in (ii)
ΔP=2ρ(v22−(A1A2v2)2)⇒ΔP=2ρv22(1−(A1A2)2)⇒3=21.25×103×v22(1−41)⇒v22=1.25×103×36×4⇒v2=8×10−2ms−1
So, the discharge rate is,
A2v2=x×10−5⇒x=10−55×10−4×8×10−2=4