The terminal velocity can be given by
vT=9η2(ρ−σ)r2g.
Clearly, vT∝r2
Let the radius of the small drops be r1 and the radius of the big drop be r2.
So,
8(34π)r13=(34π)r23⇒r1=2r2
Hence, taking the ratio
(vT)2(vT)1=(r2r1)2
⇒(vT)210=41
⇒(vT)2=40cms−1