.
Force exerted by each ball is F=ΔtΔp, here, p is momentum and t is time.
So, for one ball F=tmv−m(−v)=t2mv
Now, total force exerted by the balls on the wall is Fnet=100×F=t200mv.
JEE Main 2023 — Physics Mechanics
100 balls each of mass m moving with speed v simultaneously strike a wall normally and reflected back with same speed, in time ts. The total force exerted by the balls on the wall is
Held on 31 Jan 2023 · Verified 6 Jul 2026.
t100mv
t200mv
200mvt
100tmv
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