
The given data is
v=πms−1
By using trigonometric ratios in the triangle shown above the displacement can be found out by
sin60∘=2RAB⇒AB=R3
The formula for distance is
d=vt⇒t=vd⇒t=360∘120∘×π2πR=32R
So, the average velocity is
vavg=32R3R=233
=1.53ms−1