
As seen in the free body diagram of the object, normal force N, weight mg and force in parallel and perpendicular directions are acting.
Using Newton's law of motion
Along horizontal direction, Fcosθ=ma
⇒2cos(kx)=mvdxdv
Integrating the above relation, we have
∫0vvdv=2∫0xcos(kx)dx
⇒2mv2=k2sinkx
Thus, kinetic energy of the object will be K.E.=k2sinθ
Thus, the value of n=2.
