In horizontal circle, tension towards the centre of the circular path at any moment will provide the required centripetal force.
Therefore,
Tmax=rmv2⇒400=11×v2⇒v=20ms−1
A stone of mass 1kg is tied to end of a massless string of length 1m. If the breaking tension of the string is 400N, then maximum linear velocity, the stone can have without breaking the string, while rotating in horizontal plane, is:
Held on 31 Jan 2023 · Verified 6 Jul 2026.
20ms−1
40ms−1
400ms−1
10ms−1
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