Let R be the radius of bigger drop and r be the radius of smaller drop.
Here, volume will remain conserved, so VR=Vr.
⇒34πR3=1000×34πr3
⇒R=10r
As surface energy is stated as u=SA, here, S is surface tension and A is surface area.
Thus, ui=S(4πR2) and uf=S(4πr2)×1000
The ratio is uiuf=R21000r2
⇒uiuf=110
Hence, the value of x=1.