The angular momentum about the diameter is
Ldiameter =52MR2ω;
The moment of inertia of a sphere is ICM=52MR2. The moment of inertia about the tangent is
Itangent =ICM+MR2=52MR2+MR2=57MR2.
It is given that ω=10rads−1
Using the given relation between the moment of inertia and the angular momentum,
57MR2=x×10−2×52MR2ω⇒x=ω3.5×102=3.5×10=35